Abstract
Let lk = {z : arg z = αk, r1 ≤ |z\ ≤ r2} for k = 1, . . ., n, 0 < r1 < r2 ≤ 1, and αk ∈ ℝ; let E = Unk=1 lk; let E* = {z : arg zn = 0, r1 ≤ |z| ≤ r2}; and let ωE(z) be the harmonic measure of E with respect to the domain {z : \z\ <1} \ E. The inequality ωE(0) ≤ ωE* (0), is established, which solves the problem of Gonchar on the harmonic measure of radial slits. The proof uses the dissymmetrization method of Dubinin and the method of the extremal metric in the form of the problem of extremal partitioning into non-overlapping domains.
Original language | English |
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Pages (from-to) | 1701-1718 |
Number of pages | 18 |
Journal | Sbornik Mathematics |
Volume | 189 |
Issue number | 11-12 |
DOIs | |
State | Published - 1998 |